Area Aptitude Questions and Answers for Bank Exams - 2

Question: 6

A room is $$12{1}/{4}$$ m long and 7 m wide. The maximum length of a square tile to fill the floor of the room with whole number of tiles should be

(A) 125 cm

(B) 150 cm

(D) 200 cm

View Answer

Ans: C

Length of largest tile = H.C.F. of $$12{1}/{4}$$ m and 7 m

= H.C.F. of 12.25 m and 7 m

= H.C.F. of 1225 cm and 700 cm = 175 cm.

Question: 7

The cost of cultivating a square field at the rate of Rs. 685 per hectare is Rs. 6165. The cost of putting a fence around it at the rate off Rs. 48.75 per metre would be

(A) Rs. 23400

(B) Rs. 52650

(D) Rs. 117000

View Answer

Ans: C

Area = $${Total cost} / {Rate}$$ = $$(6165/685)$$hectare = (9 × 1000)m².

∴ Side of the square = $$√90000$$ m = 300 m.

Perimeter of the field = (300 × 4) m = 1200 m.

Cost of fencing = Rs. (1200 × 48.75) = Rs. 58500.

Question: 8

A rectangular farm has to be fenced on one long side, one short side and the diagonal. If the cost of fencing is Rs. 100 per m, the area of the farm is 1200 m² and the short side is 30 m long, how long would the job cost?

(A) Rs.7000

(B) Rs.9000

(D) Rs.15000

View Answer

Ans: C

Length = $$({1200}/{30})$$m = 40 m.

Diagonal = $$√(40)^2 + (30)^2$$m = 50 m.

Length to be fenced = (40 + 30 + 50) m = 120 m.

∴ Cost of fencing = Rs. (120 × 100) = Rs. 12000.

Question: 9

A man walking at the speed of 4 kmph croses a square field diagonally in 3 minutes. The area of the field is

(A) 18000 m²

(B) 19000 m²

(D) 25000 m²

View Answer

Ans: C

Speed of the man = $$(4 × {5}/{18})$$ m/s = $${10}/{9}$$ m/s.

Time taken = (3 × 60) sec = 180 sec.

Length of diagonal = (speed × time) = $$({10}/{9} × 180)$$ m = 200 m.

Area of the field = $${1}/{2}$$ × (diagonal)²

= $$({1}/{2} × 200 × 200)$$ m² = 20000 m²

Question: 10

Total area of 64 small squares of a chessboard is 400 sq.cm. There is 3 cm wide border around the chess board. What is the length of the side of the chessboard?

(A) 17 cm

(B) 20 cm

(D) 29 cm

View Answer

Ans: C

Area of each small square = $$({400}/{64})$$cm² = 6.25 cm².

Side of each small square = $$√6.25 $$cm = 2.5 cm.

Since there are 8 squares along each side of the chessboard.

We have

Side = [(8 × 2.5) + 6] cm = 26 cm.

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Area Aptitude Questions and Answers for Bank Exams - 2

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