# 7000+ IBPS Clerk Aptitude Questions and Answers 2024 - 2025 - 1

Question: 1

A 270 m long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?

(A) 220 m

(B) 230 m

(C) 240 m

(D) 260 m

Ans: B

Relative speed = (120 + 80) km/hr

= $$(200 × {5}/{18})$$ m/sec = $$({500}/{9})$$ m/sec.

Let the length of the other train be x metres.

Then,$${x + 270} / {9}$$ = $${500} / {9}$$

⇔ x + 270 = 500 ⇔ x = 230.

Question: 2

A 220 m long train is running with a speed of 59 kmph. In what time will it pass a man who is running at 7 kmph in the direction opposite to that in which the train is going?

(A) 10 sec

(B) 11 sec

(C) 12 sec

(D) 14 sec

Ans: C

Speed of the train relative to man = (59 + 7) kmph

= $$(66 × {5}/{18})$$ = $$({55}/{3})$$ m/sec.

Time taken by the train to cross the man

= Time takne by it to cover 220 m at

$$({55}/{3})$$ m/sec = $$(220 × {3}/{55})$$ sec = 12 sec.

Question: 3

Two train, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speedof the faster train is

(A) 30 km/hr

(B) 40 km/hr

(C) 50 km/hr

(D) 60 km/hr

Ans: D

Let the speed of the slower train be x m/sec.

Then, speed of the faster train = 2x m/sec

Relative speed = (x + 2x) m/sec = 3x m/sec.

∴ $${(100 + 100)} / {8}$$ = 3x ⇔ 24x = 200 ⇔ x = $${25}/{3}$$.

So, speed of the faster train

= $${50}/{3}$$m/sec = $$({50/3} × {18/5})$$km/hr = 60 km/hr.

Question: 4

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other is 23 seconds. The ratio of their speeds is

(A) 1 : 3

(B) 2 : 1

(C) 3 : 2

(D) 3 : 4

Ans: C

Let the speed of the two trains be x m/sec and y m/sec respectively. Then, lengh of the first train = 27 x metres, and length of the second train = 17y metres.

∴ $${27x + 17y} / {x + y}$$ = 23

⇔ 27x + 17y = 23x + 23y

⇔ 4x = 6y ⇔ $${x}/{y}$$ = $${3}/{2}$$.

Question: 5

Two trains start at the same time form A and B proceed toward each other at the speed of 75 km/hr and 50 km/hr respectively. When both meet at a point in between, one train was found to have travelled 175 km more than the other. Find the distance between A and B.

(A) 785 km

(B) 875 km

(C) 975 km

(D) 1075 km

Ans: B

Let the trains meet after t hours.

Speed of train A = 75 km/hr

Speed of train B = 50 km/hr

Distance covered by train A = 75 × t = 75t

Distance covered by train B = 50 × t = 50t

Distance = Speed × Time

According to the question,

75t – 50t = 175

⇒ 25t = 175 ⇒ t = $${175}/{25}$$ = 7 hours

∴ Distance between A and B

= 75t + 50t = 125t

= 125 × 7 = 875 km.

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