7000+ IBPS Clerk Aptitude Questions and Answers 2024 - 2025 - 1

Ans: B

Relative speed = (120 + 80) km/hr

= $$(200 × {5}/{18})$$ m/sec = $$({500}/{9})$$ m/sec.

Let the length of the other train be x metres.

Then,$${x + 270} / {9}$$ = $${500} / {9}$$

⇔ x + 270 = 500 ⇔ x = 230.

Ans: C

Speed of the train relative to man = (59 + 7) kmph

= $$(66 × {5}/{18})$$ = $$({55}/{3})$$ m/sec.

Time taken by the train to cross the man

= Time takne by it to cover 220 m at
$$({55}/{3})$$ m/sec = $$(220 × {3}/{55})$$ sec = 12 sec.

Ans: D

Let the speed of the slower train be x m/sec.

Then, speed of the faster train = 2x m/sec

Relative speed = (x + 2x) m/sec = 3x m/sec.

∴ $${(100 + 100)} / {8}$$ = 3x ⇔ 24x = 200 ⇔ x = $${25}/{3}$$.

So, speed of the faster train

= $${50}/{3}$$m/sec = $$({50/3} × {18/5})$$km/hr = 60 km/hr.

Ans: C

Let the speed of the two trains be x m/sec and y m/sec respectively. Then, lengh of the first train = 27 x metres, and length of the second train = 17y metres.

∴ $${27x + 17y} / {x + y}$$ = 23

⇔ 27x + 17y = 23x + 23y

⇔ 4x = 6y ⇔ $${x}/{y}$$ = $${3}/{2}$$.

Ans: B

Let the trains meet after t hours.

Speed of train A = 75 km/hr

Speed of train B = 50 km/hr

Distance covered by train A = 75 × t = 75t

Distance covered by train B = 50 × t = 50t

Distance = Speed × Time

According to the question,

75t – 50t = 175

⇒ 25t = 175 ⇒ t = $${175}/{25}$$ = 7 hours

∴ Distance between A and B

= 75t + 50t = 125t

= 125 × 7 = 875 km.