100+ Problems on Area and Perimeter Aptitude Questions Pdf - 2

Question: 6

The number of marble slabs of size 20 cm and 30 cm required to pave the floor of a square room of side 3 metres is

(A) 100

(B) 125

(C) 150

(D) 200

Ans: C

Number of marbles = $$({300 × 300} / {20 × 30})$$ = 150.

Question: 7

Find the cost of carpeting a room 13 m long and 9 m broad with a carpet 75 cm wide at the rate of Rs.12.40 per square metre.

(A) 150 m

(B) 152 m

(C) 154 m

(D) 156 m

Ans: D

Area of the carpet = Area of the room = (13 × 9) m2 = 117 m2.

Length of the carpet = $$({Area} / {Width})$$ = $$(117 × {4}/{3})m$$ = 156 m.

∴ Cost of carpeting = Rs. (156 × 12.40) = Rs. 1934.40.

Question: 8

The length of a rectangle is 18 cm and its breadth is 10 cm. When the length is increased to 25 cm. What will be the breadth of the rectangle if the area remains the same?

(A) 7 cm

(B) 7.1 cm

(C) 7.2 cm

(D) 7.3 cm

Ans: C

Let the breadth be b. Then,

25 x b = 18 × 10 ⇔ b = $$({18 × 10} /{25})$$cm = 7.2 cm.

Question: 9

A courtyard 25 m long and 16 m broad is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is

(A) 18000

(B) 19000

(C) 20000

(D) 25000

Ans: C

Number of bricks = $$({Area of courtyard} / {Area of 1 brick})$$

                          = $$({2500 × 1600} / {20 × 10})$$ = 20000.

Question: 10

A rectangular field has dimension 25 m by 15 m. Two mutually perpendicular passages, 2 m wide have been left in its central part and grass has been grown in rest of the field. The area (in sq.metres) under the grass is

(A) 295

(B) 299

(C) 300

(D) 375

Ans: B

Area of the field = (25 × 15)m2 = 375 m2.

Area of the passage = (25 × 2 + 15 × 2 – 2 × 2) m2 = 76 m2.

Area under grass = (375 - 76) m2 = 299 m2.

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