# 7000+ Royal Bank of Scotland Aptitude Test Questions and Answers - 1

Question: 1

A 150 m long train crosses a milestone in 15 seconds and a train of same length coming from the opposite direction is 12 seconds. The speed of the other train is

(A) 36 kmph

(B) 45 kmph

(C) 54 kmph

(D) 58 kmph

Ans: C

Speed of first train = \$\$({150}/{15})\$\$ m/sec = 10 m/sec.

Let the speed of second train be x m/sec.

Relative speed = (10 + x)m/sec.

∴ \$\${300} / {10 + x}\$\$ = 12 ⇔ 300 = 120 + 12x

⇔ 12x = 180

⇔ x = \$\${180} /{12}\$\$ = 15 m/sec.

Hence, speed of other train = \$\$(15 × {18}/{5})\$\$ kmph = 54 kmph.

Question: 2

A train travelling at 48 kmph completely crosses another train having half of its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is

(A) 300 m

(B) 400 m

(C) 450 m

(D) 500 m

Ans: B

Let the length of the first train be x metres.

Then, the length of second train is \$\$({x}/{2})\$\$ metres.

Relative speed = (48 + 42) kmph = \$\$(90 × {5}/{18})\$\$ m/sec = 25 m/sec.

∴ \$\$(x + {x}/{2}) / {25}\$\$ = 12 or \$\${3x}/{2}\$\$ = 300 or x = 200.

∴ Length of first train = 200 m.

Let the length of platform be y metres.

Speed of the first train = \$\$(48 × {5}/{18})\$\$ m/sec = \$\${40}/{3}\$\$ m/sec.

∴ (200 + y) × \$\${3}/{40}\$\$ = 45

⇔ 600 + 3y = 1800 ⇔ y = 400 m.

Question: 3

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr. What is the length of the platform?

(A) 225 m

(B) 235 m

(C) 240 m

(D) 250 m

Ans: C

Speed = \$\$(54 × {5}/{18})\$\$ m/sec = 15 m/sec.

Length of the train = (15 × 20) m = 300 m.

Let the length of the platform be x metres.

Then, \$\${x + 300} / {36}\$\$ = 15 ⇔ x + 300 = 540 ⇔ x = 240 m.

Question: 4

A 50 metre long train passes over a bridge at the speed of 30 km per hour. If it takes 36 seconds to cross the bridge, what is the length of the bridge?

(A) 200 metres

(B) 220 metres

(C) 250 metres

(D) 270 metres

Ans: C

Speed = \$\$(30 × {5}/{18})\$\$m/sec = \$\$({25}/{3})\$\$m/sec.

Time = 36 sec.

Let the length of the bridges be x metres.

Then, \$\${50 + x} / {36}\$\$ = \$\${25} / {3}\$\$ ⇔ 3 (50 + x) = 900

⇔ 50 + x = 300 ⇔ x = 250 m.

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