1000+ Bendigo Bank Aptitude Questions and Answers - 1

Question: 1

A pipe can empty a cistern in 40 minutes. Find the time in which $${3}/{4}$$ part of the cistern will be emptied.

(A) 10 minutes

(B) 20 minutes

(C) 30 minutes

(D) 40 minutes

Ans: C

We have, $${1}/{40}$$ part of the cistern is emptied in 1 minute.

∴ $${3}/{4}$$ part of the cistern is emptied in = $$40 × {3}/{4}$$ = 30 minutes.

Question: 2

A cistern is normally filled with water in 10 hours but takes 5 hours loner to fill because of a leak in its bottom. If the cistern is full, then the leak will empty the cistern in

(A) 20 hours

(B) 30 hours

(C) 40 hours

(D) 60 hours

Ans: B

In one hour = $${1/10} - {1/15}$$ = $${1}/{30}$$ of the cistern will be empty.

Question: 3

Two taps can separately fill a cistern in 10 minutes and 15 minutes, respectively. When the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in

(A) 7 minutes

(B) 9 minutes

(C) 13 minutes

(D) 23 minutes

Ans: B

Work done by the waste pipe in 1 minute

= $$({1/10} + {1/15}) - {1/18}$$

= $$({1/6} - {1/18})$$ = $${1}/{9}$$

∴ The waste pipe can empty the cistern in 9 minutes.

Question: 4

A cistern is provided by two taps A and B. Tap A can fill it in 20 minutes and tap B in 25 minutes. Both the taps are kept open for 5 minutes and, then the second is turned off. The cistern will be completely filled in another

(A) 10 minutes

(B) 11 minutes

(C) 12 minutes

(D) 15 minutes

Ans: B

Part filled in 1 minute = $${1/20} + {1/25}$$ = $${9/100}$$

Part filled in 5 minutes = $${9}/{100} × 5$$ = $${9}/{20}$$.

Unfilled part = $$1 - {9}/{20}$$ = $${11}/{20}$$.

This is to be filled by A alone and hence will be filled
in $$20 × {11}/{20}$$ = 11 minutes.

Question: 5

Two pipes A and B can separately empty a cistern in 12 hours and 15 hours, respectively. In what time will the cistern be emptied, if both the pipes are opened together?

(A) 5 hours 30 minutes

(B) 6 hours 40 minutes

(C) 7 hours

(D) 9 hours

Ans: B

Here, X = 12 and Y = 15.

∴ The cistern will be empty in

= $$({XY} /{X + Y})$$ hours

= $${12 × 15}/{12 + 15}$$hours

= $${20}/{3}$$ hours or 6 hours 40 minutes.

Related Questions