# 7000+ United Overseas Bank Exam Interview Questions and Answers - 1

Question: 1

Train A crosses a stationary train B in 50 seconds and a pole in 20 seconds with the same speed. The length of the train A is 240 metres. What is the length of the stationary train B?

(A) 260 metres

(B) 300 metres

(C) 320 metres

(D) 360 metres

Ans: D

Speed of train A = \$\$({240}/{20})\$\$m/sec = 12 m/sec.

Let the length of train B be x metres.

Then, \$\${240 + x} / {12}\$\$ = 50

⇔240 + x = 600 ⇔ x = 360 m.

Question: 2

Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/ hr) is

(A) 18

(B) 36

(C) 72

(D) 94

Ans: B

Let the speed of each train be x m/sec.

Then, relative speed of the two trains = 2x m/sec.

So, 2x = \$\${(120 + 120)}/{12}\$\$ ⇔ 2x = 20 ⇔ x = 10.

∴ Speed of each train = 10 m/sec

= \$\$(10 × {18}/{5})\$\$km/hr = 36 km/hr.

Question: 3

What is the speed of a train if it overtakes two persons who are walking in the same diretion at the rate of a m/s and (a + 1) m/s and passes them completely in b seconds and (b + 1) seconds respectively?

(A) (a + b) m/s

(B) (a + b + 1) m/s

(C) (2a + 1) m/s

(D) \$\${(2a + 1)} / {2}\$\$ m/s

Ans: B

Let the length of the train be x metres and its speed be y m/s.

Then, \$\${x} / {y - a}\$\$ = b and \$\${x} / {y - (a + 1)}\$\$ = (b + 1)

⇔ x = b(y - a) and x = (b + 1) (y - a - 1)

⇔ b(y - a) = (b + 1) (y - a - 1)

⇔ by - ba = by - ba - b + y - a - 1

⇔ y = (a + b + 1).

Question: 4

A train 800 metres long is running at speed of 78 km/hr? if it crosses a tunnel in 1 minute, then the length of the tunnel (in metres) is

(A) 130

(B) 250

(C) 350

(D) 500

Ans: D

Speed = \$\$(78 × {5}/{18})\$\$ m/sec = \$\$({65}/{3})\$\$ m/sec.

Time = 1 minute = 60 sec.

Let the length of the tunnel be x metres.

Then, \$\${800 + x} / {60}\$\$ = \$\${65}/{3}\$\$

⇔ 3(800 + x) = 3900 ⇔ x = 500.

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