100+ Problems on Trains Aptitude Questions and Answers - 1

Question: 1

A train 270 meters long is moving at a speed of 25 km/hr. It will cross a man coming from the opposite direction at a speed of 2 km per hour is

(A) 24 seconds

(B) 28 seconds

(C) 32 seconds

(D) 36 seconds

Ans: D

Relative speed = (25 + 2) km/hr = 27 km/hr

= \$\$(27 × {5} / {18})\$\$ m/sec = \$\$({15} / {2})\$\$ m/sec

∴ Time taken by the train to pass the man = \$\$(270 × {2} / {15})\$\$ sec = 36 sec.

Question: 2

A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

(A) 120 metres

(B) 150 metres

(C) 180 metres

(D) 200 metres

Ans: B

Speed = \$\$(60 × {5} / {18})\$\$m/sec = \$\$({50} / {3})\$\$m/sec.

Length of the train = (Speed x Time) = \$\$({50} / {3} × 9)\$\$m = 150m.

Question: 3

A train takes 9 sec to cross a pole. If the speed of the train is 48 kmph, then length of the train is

(A) 80 m

(B) 90 m

(C) 120 m

(D) 150 m

Ans: C

Time taken by train to cross a pole = 9 sec.

Distance covered in crossing a pole = length of train

Speed of train = 48 km/hr

= \$\$({48 × 5} / 18)\$\$ m/sec

= \$\${40} / {3}\$\$ m/sec

∴ Length of train = speed x time = \$\${40} / {3} × 9\$\$ = 120 m

Question: 4

Two trains 240 metres and 270 metres in length are running towards each other on parallel lines, one at the rate of 60 kmph and another at 48 kmph. How much time will they take to cross each other?

(A) 14 sec.

(B) 15 sec.

(C) 16 sec.

(D) 17 sec.

Ans: D

Relative speed of the two trains = (60 + 48) kmph

= 108 kmph

= \$\$(108 × {5} / {18})\$\$m/sec = 30 m/sec.

Time taken by the trains to pass each other
= Time taken to cover (240 + 270) m at 30 m/sec = \$\$({510} / {30})\$\$ sec = 17 sec.

Question: 5

The time taken by a train 180 m long, travelling at 42 kmph, in pasing a person walking in the same direction at 6 kmph, will be

(A) 16 sec

(B) 18 sec

(C) 21 sec

(D) 24 sec

Ans: B

Speed of train relative to man = (42 – 6) kmph = 36 kmph

= \$\$(36 × {5} / {18})\$\$m/sec = 10 m/sec.

∴ Time taken to pass the man = \$\$({180} / {10})\$\$ sec = 18 sec.

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