1000+ Tsehay Bank Exam Questions and Answers Pdf - 1

Ans: D

Out of 52 cards, 13 cards are of diamond series and 3 cards are queen

n(E) = 13 + 3 = 16; n(S) = 52

P(E) = $${16}/{52}$$ = $${4}/{13}$$

Ans: C

Number of possible events = 36

E = Event of getting product of 2 results even

Number of favourable events = {(1, 6), (1, 4) (1, 2) (2, 1) (2, 2)
(2, 3) (2, 4) (2, 5) (2, 6) (3, 2) (3, 4) (3, 6) (4, 1) (4, 2) (4, 3) (4, 4), (4, 5), (4, 6), (5, 2) (5, 4) (5, 6) (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)} = 27

∴ P(E) = $${n(E)} / {n(S)}$$ = $${27}/{36}$$ = $${3}/{4}$$.

Ans: C

The number of possible events when two cards are drawn together from a pack of 52 cards

= ⁵²C₂ = $${52 × 51} / {1 × 2}$$ = 26 × 51 = 1326

Number of possible events to draw a spade = ¹³C₁ = 13 ways.

Number of possible events to draw a heart = ¹³C₁ = 13 ways.

E = Event of getting 1 spade and 1 heart n(E) = 13 × 3 = 169

∴ P(E) = $${n(E)}/{n(S)}$$ = $${169}/{1326}$$ = $${13}/{102}$$

Ans: B

Total number of favourable events n(S) = 8 + 7 + 6 = 21

Total number of possible events = 7

E = event of getting neither red or green – event of getting blue.

∴ P(E) = $${7}/{21}$$ = $${1}/{3}$$

Ans; D

When two dice are thrown, total number of results, n(S) 6 × 6 = 36

Event of getting total of 8 or 9

E = {(2,6), (3, 5), (4, 4), (3, 6), (4, 5)}

P(E) = $${n(E)} / {n(S)}$$ = $${5}/{36}$$