# 7000+ Maybank Exam Interview Questions and Answers - 1

Question: 1

The Ghaziabad-Hapur-Meerut EMU and the Meerut-Hapur-Ghaziabad EMU start at the same time from Ghaziabad and Meert and proceed towards each other at 16 km/hr and 21 km/hr respectively. When they meet, it is found that one train has travelled 60 km more than the other. The distance between two stations is

(A) 440 km

(B) 442 km

(C) 444 km

(D) 450 km

Ans: C

At the time of meeeting, let the distance travelled by the first train be x km.

Then, distance travelled by the second train is (x + 60) km.

∴\$\${x}/{16}\$\$ = \$\${x + 60} / {21}\$\$ ⇒ 21x = 16x + 960 ⇒ 5x = 960 ⇒ x = 192.

Hence, distance between two stations = (192 + 192 + 60) km = 444 km.

Question: 2

A train travelling at a speed of 75 mph enters a tunnel \$\$3{1}/{2}\$\$ miles long. The train is \$\${1}/{4}\$\$ mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?

(A) 2.5 min

(B) 3 min

(C) 3.2 min

(D) 3.5 min

Ans: B

Total distance covered = \$\$({7/2} + {1/4})\$\$ miles = \$\${15}/{4}\$\$ miles.

∴ Time taken = \$\$({15}/{4 × 75})\$\$ hrs = \$\${1}/{20}\$\$ hrs

= \$\$({1}/{20} × 60)\$\$ min. = 3 min.

Question: 3

A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train?

(A) 66 km/hr

(B) 72 km/hr

(C) 81 km/hr

(D) 84 km/hr

Ans: C

4.5 km/hr = \$\$(4.5 × {5}/{18})\$\$m/sec = \$\${5}/{4}\$\$ m/sec = 1.25 m/sec, and

5.4 km/hr = \$\$(5.4 × {5}/{18})\$\$m/sec = \$\${3}/{2}\$\$ m/sec = 1.5 m/sec.

Let the speed of the train be x m/sec.

Then, (x - 1.25) × 8.4 = (x - 1.5) × 8.5

⇔ 8.4 x – 10.5 = 8.5 x – 12.75

⇔ 0.1 x = 2.25 ⇔ x = 22.5.

∴ Speed of the train = \$\$(22.5 × {18}/{5})\$\$km/hr = 81 km/hr.

Question: 4

A train moving at 15 m/sec takes 20 seconds to pass a cyclist moving in the same direction as that of the train. How much time will the train need to pass the cyclist, if the cyclist moves in a direction opposite to that of the train and if the speed of the cyclist is 5 m/sec and the length of the cycle is 1 m?

(A) 10 sec

(B) 10.05 sec

(C) 11 sec

(D) 12 sec

Ans: A

Let the length of the train be x metres.

Then, distance covered in passing the cyclist = (x + 1) m.

∴ x + 1 = (15 - 5) × 20 = 200 ⇔ x = 199 m.

So, required time = \$\$[{(x + 1)} / {15 + 5}]\$\$sec = \$\$({200}/{20})\$\$ sec = 10 sec.

Question: 5

The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is

(A) 200 m

(B) 245 m

(C) 300 m

(D) 320 m

Ans: B

Speed = \$\$(45 × {5}/{18})\$\$m/sec = \$\$({25}/{2})\$\$m/sec; Time = 30 sec.

Let the length of bridge be x metres.

Then, \$\${130 + x} / {30}\$\$ = \$\${25}/{2}\$\$

⇔ 2(130 + x) = 750 ⇔ = 245 m.

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