Top 100+ Percentages Aptitude Online Test - 2

Ans: B

Let the original price of sugar be Rs. 10 per kg.

Then, original expenditure = Rs. (10 × 10) = Rs. 100.

New expenditure = 110% of 100 = Rs. 100.

New price of sugar = 132% of 10 = Rs. 13.20.

New consumption = $$({110} / {13.20})$$ kg = $${25}/{3}$$ kg = $$8{1}/{3}$$kg

Ans: A

Let number of students who appeared at the examinatic be x.

Passed percentage = 96%

Failed percentage = 4%

According to given information we get

Unsuccessful students ⇒ 4%

∴ 4% of x = 500

⇒ $$({x ×4}/{100})$$ = 500

⇒ x = $$({500 × 100} / {4})$$ = 12500.

Ans: B

Weight of water in 60 gms mixture = 75% of 60 = $$({75}/{100} × 60)$$ = 45 gm.

Weight of water in 75 gms mixture = (45 + 15) gm = 60 gm.

∴ Required percentage = $$({60}/{75} × 100)%$$ = 80%.

Ans: C

(23.6% of 1254) – (16.6% of 834)

= $$({236}/{10} × {1}/{100} × 1254)$$ – $$({166}/{10} × {1}/{100} × 834)$$

= $${1}/{1000}$$(236 × 1254 - 166 × 834)

= $${12}/{1000}$$(24662 – 11537) = $$({12 × 13125} / {1000})$$ = 157.5.

Ans: B

Let the total number of customers be x.

Then, number of customers who purchase hats = 15% of 40% of x

= $$({15}/{100} × {40}/{100} × x)$$ = $${6x}/{100}$$

= 6% of x.

∴ Required percentage = 6%.