1000+ Quantitative Aptitude for Bank Exam Question and Answer - 1

Question: 1

The average of 50 numbers is 38. If two numbers 45 and 55 are discarded, the average of the remaining set of numbers is

(A) 36.5

(B) 37.0

(C) 37.5

(D) 38.5

Ans: C

Average of the remaining set of numbers

= $${50 × 38 - (45 + 55)} / {50 - 2}$$ = $${1900 - 100} / {48}$$ = 37.5.

Question: 2

In a cricket team of 11 boys, one player weighing 42 Kg, is injured and replaced by another player. If the average weight of the team is increased by 100 gm as a result of this, then what is the weight of the new player?

(A) 42.1 Kg

(B) 43.1 Kg

(C) 44.1 Kg

(D) 45.1 Kg

Ans: B

Average weight of 11 boys is increased by 100 gm = (0.1 Kg)

∴ Their total increase in weight = 0.1 × 11 = 1.1 Kg

Hence, the weight of the boy = 42 + 1.1 = 43.1 Kg.

Question: 3

A man travels by a car to his office at 60 km/h and returns home along the same route at 20 km/h. Find the average speed of his whole journey.

(A) 25 km/h

(B) 30 km/h

(C) 40 km/h

(D) 50 km/h

Ans: B

Average speed = $${20 × 60 × 20} / {60 + 20}$$ = $${2 × 60 × 20} / {80}$$ = 30 km/h.

Question: 4

How many runs must he make in his next innings so as to increase his average of runs by 4?

(A) 70

(B) 76

(C) 80

(D) 82

Ans: B

Total score in 10 innings = 32 × 10 = 320

To raise the average to 36,

Total score after 11 innings = 36 x 11 = 396

∴ Runs he has to take in the 11th innings = 396 - 320 = 76.

Question: 5

Average age of 15 students of a class is 15 years. Out of these the average age of 5 students is 14 years and that of the other 9 students is 16 years. The age of the 15th student is

(A) 10 years

(B) 11 years

(C) 12 years

(D) 14 years

Ans: B

Total age of 15 students = 15 × 15 = 225 years

Sum of ages of 5 students = 5 × 14 = 70 years

Sum of ages 9 students = 9 × 16 = 144 years

∴ Age of 15th student = (1) – (2) – (3) = 225 – (70 + 144) = 11 years.

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